Johnny Clayton v Luke Humphries Betting Odds
Final Johnny Clayton 8-4 Luke Humphries
Johnny Clayton v Luke Humphries was played on 11 October 2026. Below is how the market closed: the last price before the start at each bookmaker. Luke Humphries held at 1.50 all the way to kickoff, the best price on offer.
Automatically generated from our odds data
How the market closed
5 bookmakers- Johnny Clayton 38.4% average price 2.49 happened
- Luke Humphries (favourite) 61.6% average price 1.55
The chance the closing market gave each outcome with the margin taken out, from the average closing price across every bookmaker in our archive for this game (decimal; a fraction of an average says little); average payout 94.5%. The market made Luke Humphries the favourite at 61.6%. Johnny Clayton won.
Closing odds by bookmaker
| Bookmaker | Johnny Clayton1 | Luke Humphries2 | Payout |
|---|---|---|---|
| 2.63 | 1.50 | 95.5% | |
| 1.94 | 1.84 | 94.4% |
Each bookmaker's last price before the start, among the bookmakers we compare; the best price in each column is marked. Past prices, not a tip.
Did you beat the closing price?
Enter the price you took in the closing line value calculator, with this game's average close filled in: Johnny Clayton, Luke Humphries. One price proves little either way; beating the close over many bets is the sign of value.
How the odds moved before kickoff
| Selection | First best price | Closing best price | Move | Chance | Details |
|---|---|---|---|---|---|
| Johnny Clayton | 2.85 Unibet, Sun 11 Oct | 2.88 Unibet | +1.1%1 of 2 bookmakers drifted | 35%, unchanged | |
| Luke Humphries | 1.50 Bet365, Sun 11 Oct | 1.50 Bet365 | No change | 65%, unchanged |
Closing odds
| Bookmaker | Johnny Clayton | Luke Humphries |
|---|---|---|
| Bet365 | 2.63 | 1.50 |
| Unibet | 2.88 | 1.42 |
Best prices across the bookmakers we compare, captured every few minutes up to kickoff since Sun 11 Oct. Chance is the average of the bookmakers' prices with their margin removed. Price moves show what bookmakers did, not what will happen.